We need to form 3-digit numbers using the digits 2, 3, 5, 6, 7, 9
✅ Divisible by 5
✅ No repeated digits

Step 1: Check divisibility by 5 🔢
For a number to be divisible by 5, its last digit must be 5.
So, the last digit is fixed as 5. 🛑5

Now, we need to choose the first and second digits from the remaining numbers:
{2, 3, 6, 7, 9} (5 is already used).

Step 2: Choose the first digit (Hundreds place) 💯
The first digit can be any of the 5 remaining digits:
2, 3, 6, 7, 9
So, we have 5 choices.

Step 3: Choose the second digit (Tens place) 🔢
Now, one digit is already used in the hundreds place.
That leaves us with 4 remaining choices.

Step 4: Multiply the choices ✖️
Total numbers that can be formed:

5×4=205 \times 4 = 20

🎯 Final Answer:
There are 20 different 3-digit numbers that can be formed under these conditions! 🎊🚀