A can finish a work in 24 days, B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in:
📊 Let’s Solve the Problem! 🤔
Step 1: Calculate the work done by B and C in 1 day
– B’s work in 1 day = 1/9
– C’s work in 1 day = 1/12
– Combined work in 1 day = B’s work + C’s work
= 1/9 + 1/12
= (4+3)/36
= 7/36
Step 2: Calculate the work done by B and C in 3 days
Work done in 3 days = Combined work in 1 day × 3
= (7/36) × 3
= 7/12
Step 3: Calculate the remaining work
Total work = 1
Remaining work = Total work – Work done by B and C
= 1 – 7/12
= 5/12
Step 4: Calculate the time taken by A to finish the remaining work
A’s work in 1 day = 1/24
Time taken by A = Remaining work / A’s work in 1 day
= (5/12) / (1/24)
= (5/12) × 24
= 10 days
The final answer is: A took 10 days to finish the remaining work. 📆
