Arithmetic (Problems on Ages)
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1) The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 5 years ago.
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2) The average of a husband and his wife was 23 years at the time of their marriage. After 5 years, the average age of the husband, wife and child was 20 years. A child was born immediately after one year of their marriage. If the present age of the child is 8 years, the present age of the wife is:
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3) The sum of the present ages of a father and his son is 48 years. Four years ago, father’s age was three times the age of the son. Find the present age of the son.
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4) The sum of the present ages of a father and his son is 45 years. Five years ago, the product of their ages was 124. Find their present ages.
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5) The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 5 years ago.
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6) The average of a husband and his wife was 23 years at the time of their marriage. After 5 years, the average age of the husband, wife and child was 20 years. A child was born immediately after one year of their marriage. If the present age of the child is 8 years, the present age of the wife is:
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7) The sum of the present ages of a father and his son is 48 years. Four years ago, father’s age was three times the age of the son. Find the present age of the son.
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8) The sum of the present ages of a father and his son is 45 years. Five years ago, the product of their ages was 124. Find their present ages.
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9) The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 5 years ago.
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10) The average of a husband and his wife was 23 years at the time of their marriage. After 5 years, the average age of the husband, wife and child was 20 years. A child was born immediately after one year of their marriage. If the present age of the child is 8 years, the present age of the wife is:
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11) The sum of the present ages of a father and his son is 48 years. Four years ago, father’s age was three times the age of the son. Find the present age of the son.
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12) The sum of the present ages of a father and his son is 45 years. Five years ago, the product of their ages was 124. Find their present ages.
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13) The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 5 years ago.
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14) The average of a husband and his wife was 23 years at the time of their marriage. After 5 years, the average age of the husband, wife and child was 20 years. A child was born immediately after one year of their marriage. If the present age of the child is 8 years, the present age of the wife is:
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15) The sum of the present ages of a father and his son is 48 years. Four years ago, father’s age was three times the age of the son. Find the present age of the son.
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16) The sum of ages of a father and a son is 45 years. Five years ago, the product of their ages was 124. Find their present ages.
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17) The ratio of the present ages of two brothers is 1:2 and the ratio of their ages 5 years hence is 1:2. Find the ratio of their ages 8 years ago.
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18) A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B?
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19) The present ages of three persons in proportions are 4:7:9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
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20) The present age of a father is 3 years more than three times the age of his son. Three years hence, father’s age will be 10 years more than twice the age of the son. The ratio of their present ages is:
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21) The sum of the present ages of a father and his son is 60 years. Six years ago, father’s age was five times the age of the son. After 6 years, son’s age will be:
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