speed of the train 1 = 46km/hr, speed of the train 2 = 36km/hr, Relative speed = 46 - 36 = 10km/hr. t = 36sec. 10 * 5/18 = 50/18 m/sec. S = d/t. S = L1 + L2. Here two trains have equal lengths....
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- Author: Priya
speed of the train 1 = 46km/hr, speed of the train 2 = 36km/hr, Relative speed = 46 - 36 = 10km/hr. t = 36sec. 10 * 5/18 = 50/18 m/sec. S = d/t. S = L1 + L2. Here two trains have equal lengths....
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