A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:
papay dey Answered question 4 days ago
Let’s denote the present age of the son as x.
The man is 24 years older than his son, so the man’s present age is x + 24.
In two years, the son’s age will be x + 2, and the man’s age will be x + 24 + 2 = x + 26.
According to the problem, in two years, the man’s age will be twice the age of his son:
x + 26 = 2(x + 2)
Expand the equation:
x + 26 = 2x + 4
Subtract x from both sides:
26 = x + 4
Subtract 4 from both sides:
22 = x
The present age of the son is 22 years.
papay dey Answered question 4 days ago