Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
Anonymous Answered question February 7, 2025
u=27s
v=17s
Cross = 23s.
l1 = 27x.
l2 = 17y.
23 = l1 + l2/x + y
23 = 27x + 17y/x + y.
23x + 23y = 27x + 17y.
4x – 6y = 0.
4x = 6y.
x/y = 6/4.
x/y = 3/2.
bijay Answered question February 7, 2025
Time taken by train 1 = 27s.
Time taken by train 2 = 17s.
Time taken for them to cross each other = 23s
Time taken by train 2 = 17s.
Time taken for them to cross each other = 23s
Let the velocity of train 1 be v1 and that of train 2 is v2, and their lengths be l1 and l2 resp.
Net velocity when they cross each other v = v1 + v2.
Thus;
(l1+l2) = (v1+v2)x23—> i
and
l1 = v1 * 27 and l2 = v2 * 17—> ii
By Replacing ii in i.
27v1 + 17v2 = 23(v1+v2)
4v1 = 6v2
v1:v2 = 3:2.
Crix Briva Changed status to publish February 7, 2025
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