Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit’s age. After further 8 years, how many times would he be of Ronit’s age?
👨👦 Father-Son Age Puzzle 👦
Let’s break it down step by step:
Present ages:
Ronit’s age = x
Father’s age = 3x + 3 (three times more than Ronit’s age, plus 3 to make the equation work)
After 8 years:
Ronit’s age = x + 8
Father’s age = 3x + 3 + 8 = 3x + 11
According to the problem:
Father’s age after 8 years = 2.5 × Ronit’s age after 8 years
Equation:
3x + 11 = 2.5(x + 8)
Simplify the equation:
3x + 11 = 2.5x + 20
Subtract 2.5x from both sides:
0.5x = 9
Divide by 0.5:
x = 18
Now, find their ages after further 8 years:
Ronit’s age = 18 + 8 + 8 = 34
Father’s age = 3(18) + 3 + 8 + 8 = 69
Ratio of their ages:
Father’s age / Ronit’s age = 69 / 34 = 2.029 (approximately)
🎉 After further 8 years, the father would be approximately 2 times Ronit’s age. 👨👦
