📊 Let’s Solve the Problem! 🤔

Let’s assume:

– A takes x days to finish the work.
– B takes x/2 days to finish the work (since A takes twice as much time as B).
– C takes x/3 days to finish the work (since A takes thrice as much time as C).

Step 1: Calculate the work done by each person in 1 day
– A’s work in 1 day = 1/x
– B’s work in 1 day = 1/(x/2) = 2/x
– C’s work in 1 day = 1/(x/3) = 3/x

Step 2: Calculate the combined work done by A, B, and C in 1 day
Combined work in 1 day = A’s work + B’s work + C’s work
= 1/x + 2/x + 3/x
= 6/x

Step 3: Use the information that A, B, and C together can finish the work in 2 days
Combined work in 2 days = 1 (since they finish the work)
Combined work in 1 day = 1/2
6/x = 1/2
x = 12

Step 4: Calculate the time taken by B to finish the work alone
B’s time = x/2
= 12/2
= 6 days

The final answer is: B can do the work alone in 6 days. 📆