In how many ways can a group of 5 men and 2 women be made out of a total of 7 men and 3 women?
Step 1: Identify the given people ๐จโ๐ผ๐ฉโ๐ผ
We have:
- 7 men ๐จ๐จ๐จ๐จ๐จ๐จ๐จ
- 3 women ๐ฉ๐ฉ๐ฉ
We need to form a group of 5 men and 2 women. โ
Step 2: Choose 5 men from 7 ๐จโ๐ผ๐จโ๐ผ๐จโ๐ผ๐จโ๐ผ๐จโ๐ผ
Since we are selecting 5 men out of 7, we use combinations:
Waysย toย chooseย 5ย men=(75)=7!5!(7โ5)!\text{Ways to choose 5 men} = \binom{7}{5} = \frac{7!}{5!(7-5)!}Waysย toย chooseย 5ย men=(57โ)=5!(7โ5)!7!โ =7!5!2!=7ร62ร1=21= \frac{7!}{5!2!} = \frac{7 \times 6}{2 \times 1} = 21=5!2!7!โ=2ร17ร6โ=21
So, we can choose the men in 21 ways. ๐
Step 3: Choose 2 women from 3 ๐ฉโ๐ผ๐ฉโ๐ผ
Now, we select 2 women out of 3:
Waysย toย chooseย 2ย women=(32)=3!2!(3โ2)!\text{Ways to choose 2 women} = \binom{3}{2} = \frac{3!}{2!(3-2)!}Waysย toย chooseย 2ย women=(23โ)=2!(3โ2)!3!โ =3!2!1!=3ร22ร1=3= \frac{3!}{2!1!} = \frac{3 \times 2}{2 \times 1} = 3=2!1!3!โ=2ร13ร2โ=3
So, we can choose the women in 3 ways. ๐
Step 4: Calculate the total number of ways ๐ข
Since the selection of men and women are independent, we multiply both results:
Totalย ways=21ร3=63\text{Total ways} = 21 \times 3 = 63Totalย ways=21ร3=63
๐ฏ Final Answer:
The group of 5 men and 2 women can be formed in 63 different ways! ๐๐ฅณ